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Python · 2026

Pathfinder

BFS, uniform-cost search and A* from scratch on terrain where climbing costs more. A* expanded 41 nodes where BFS needed 112.

When
Mar 2026 to Jun 2026
My role
Solo build
Stack
Python · BFS · Dijkstra · A*
nodes, A*
41
nodes, UCS
75
nodes, BFS
112
BFS route cost
+24%

Problem

Shortest is not the same as cheapest. On terrain where moving uphill costs more, a route with fewer steps can be the expensive one, and a search that ignores cost will happily pick it.

Approach

Implemented breadth-first search, uniform-cost search (Dijkstra) and A* from scratch in Python. Each grid cell has an elevation, moving costs 1 plus any climb, obstacles block movement, and moves are four-directional.

A* runs with two admissible heuristics, Euclidean and Manhattan distance, and every algorithm runs on the same set of test maps, from a small maze to a 20 by 20 random terrain, so the comparison is fair.

Impact

On the same path, A* expanded 41 nodes against uniform-cost search's 75 and BFS's 112. On the 20 by 20 map, BFS's route cost 24% more than the optimal one, which is the whole argument for cost-aware search in one number.

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